bash-cmd-sub-and-declare

bash command substitution return value being masked

tags: learning linux

content

• for a line like local var=$(do_something), LSP throws this error:

Declare and assign separately to avoid masking return values.

• it means, the return values from do_something will not be captured and will be lost
• because the execution is:
  1. do_something is executed
  2. var is assigned
• so if i run echo $? after local var=$(do_something), the result is always 0, because the return code of variable assignment is always 0

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